Class interval 0 – 10 10 – 20 20 – 30 30 – 40 40 – 50 50 – 60
Frequency (fi) 8 7 f1 8 8 f2
Marks obtained |
Number of students |
More than 100 |
60 |
More than 200 |
55 |
More than 300 |
43 |
More than 400 |
36 |
More than 500 |
32 |
More than 600 |
30 |
More than 700 |
17 |
More than 800 |
8 |
More than 900 |
3 |
Days 10-20 20-30 30-40 40-50 50-60 60-70 70-80 Total |
No. of absentees 12 30 x1 65 x2 25 18 229 |
Class Interval |
Frequency |
0 − 20 |
3 |
20 − 40 |
9 |
40 − 60 |
12 |
60 − 80 |
12 |
80 − 100 |
x |
100 − 120 |
6 |
120 − 140 |
5 |
140 − 160 |
12 |
160 − 180 |
5 |
180 − 200 |
7 |
Annual income(in Rs) |
Number of families |
100000 – 200000 |
8 |
200000 – 300000 |
9 |
300000 – 400000 |
17 |
400000 – 500000 |
18 |
500000 – 600000 |
14 |
600000 – 700000 |
6 |
700000 – 800000 |
3 |
Class |
1st weighing |
|
0-5 |
a |
x |
5-10 |
b |
y |
10-15 |
11 |
40 |
15-20 |
52 |
50 |
20-25 |
75 |
30 |
25-30 |
22 |
28 |
(A) (B)
0 – 10 4 4 59
10 − 20 8 12 55
20 − 30 11 23 47
30 − 40 15 38 36
40 − 50 12 50 21
50 − 60 6 56 9
60 − 70 3 59 3
Draw a ‘more than’ ogive curve & a ‘less than’ ogive curve of the above data.
Daily income (in Rs) |
100 − 120 |
120 − 140 |
140 − 160 |
160 − 180 |
180 − 200 |
Number of workers |
12 |
14 |
8 |
6 |
10 |
Convert the distribution above to a less than type cumulative frequency distribution, and draw its ogive.
Weight (in kg) |
Number of students |
Less than 38 |
0 |
Less than 40 |
3 |
Less than 42 |
5 |
Less than 44 |
9 |
Less than 46 |
14 |
Less than 48 |
28 |
Less than 50 |
32 |
Less than 52 |
35 |
Draw a less than type ogive for the given data. Hence obtain the median weight from the graph verify the result by using the formula.
Production yield (in kg/ha) |
50 − 55 |
55 − 60 |
60 − 65 |
65 − 70 |
70 − 75 |
75 − 80 |
Number of farms |
2 |
8 |
12 |
24 |
38 |
16 |
Change the distribution to a more than type distribution and draw ogive.
Length (in mm) |
Number or leaves fi |
118 − 126 |
3 |
127 − 135 |
5 |
136 − 144 |
9 |
145 − 153 |
12 |
154 − 162 |
5 |
163 − 171 |
4 |
172 − 180 |
2 |
Find the median length of the leaves.
(Hint: The data needs to be converted to continuous classes for finding the median, since the formula assumes continuous classes. The classes then change to 117.5 − 126.5, 126.5 − 135.5… 171.5 − 180.5)
Class interval |
Frequency |
0 − 10 |
5 |
10 − 20 |
x |
20 − 30 |
20 |
30 − 40 |
15 |
40 − 50 |
y |
50 − 60 |
5 |
Total |
60 |
Number of mangoes |
50 − 52 |
53 − 55 |
56 − 58 |
59 − 61 |
62 − 64 |
Number of boxes |
15 |
110 |
135 |
115 |
25 |
Find the mean number of mangoes kept in a packing box. Which method of finding the mean did you choose?
Prepared By:
Mr. Vijay Chawla
Email [email protected]
9899114400