Maths by Mr. M. P. Keshari
Example 5. Calculate the arithmetic mean of the following frequency distribution:
Class Interval | 0-30 | 30-60 | 60-90 | 90-120 | 120-150 | 150-180 |
Frequency | 12 | 21 | 34 | 52 | 20 | 11 |
Solution:-
Class interval | Frequency | xi | di = xi - 105 | fi di |
0-30 | 12 | 15 | -90 | |
30-60 | 21 | 45 | -60 | |
60-90 | 34 | 75 | -30 | |
90-120 | 52 | 105 = a | 0 | -0 |
120-150 | 20 | 135 | 30 | |
150-180 | 11 | 165 | 60 | |
Here, a = 105
Arithmetic mean =
Subjects | Maths (Part-1) by Mr. M. P. Keshari |
Chapter 9 | Circle |
Chapter 10 | Tangents to a circle |
Chapter 11 | Geometrical Construction |
Chapter 12 | Troigonometry |
Chapter 13 | Height and Distance |
Chapter 14 | Mensuration |
Chapter 15 | Statistics |
Chapter 16 | Probability |
Chapter 17 | Co-ordinate Geometry |