Cyclic Quadrilaeral
Quadrilateral whose all the (four) vertius lie on a circle is called a cyclic quadrilateral.
Theorem 4:- The sum of the either pair of the opposite angle of a cyclic quadrilateral is 1800
Give: - A cyclic quadrilateral ABCD
To prove:-
Construction:- Let O be the centre of the circle passing through A, B, C and D. OB and OD are joined.
Proof:-
= x/2, say (Theo.2)
and
= y/2, say (Theo.2)
Adding (i) and (ii) we get
As the sum of the angles of a quadrilateral is 3600, there fore,
Example 6. In the adjoining figure,
Solution:- As BD = DC
ABCD is a cyclic quadrilateral.
Subjects | Maths (Part-1) by Mr. M. P. Keshari |
Chapter 9 | Circle |
Chapter 10 | Tangents to a circle |
Chapter 11 | Geometrical Construction |
Chapter 12 | Troigonometry |
Chapter 13 | Height and Distance |
Chapter 14 | Mensuration |
Chapter 15 | Statistics |
Chapter 16 | Probability |
Chapter 17 | Co-ordinate Geometry |