Delhi 2007:
5.b) Consider the following tables. Write SQL command for the statements (i)to(iv)and give outputs for the SQL quries (v) to (viii). 6
TABLE : SENDER
| SenderID | SenderName | Sender Address | Sender City |
|---|---|---|---|
| ND01 | R jain | 2,ABC Appts | New Delhi |
| MU02 | H sinha | 12, Newton | Mumbai |
| MU1 5 | S haj | 27/ A,Park Street | New Delhi |
| ND5 0 | T Prasad | 122-K,SDA | Mumbai |
TABLE :RECIPIENT
| RecID | SenderID | ReCName | RecAddress | ReCCity |
|---|---|---|---|---|
| KO05 | ND01 | RBajpayee | 5,Central Avenue | Kolkata |
| ND08 | MU0 2 | S Mahajan | 116, A Vihar | NewDelhi |
| MU19 | ND01 | H sing | 2A,Andheri East | Mumbai |
| MU32 | MU1 5 | PK Swamy | B5, CS erminus | Mumbai |
| ND48 | ND50 | S Tripathi | 13, B1 D,Mayur Vihar | NewDelhi |
(i) To display the names of all senders from Mumbai.
Ans: Select * from Sender where SenderCity =’Mumbai’;
(ii) To display the recID, senderName, senderAddress, RecName, RecAddress for every recipt.
Ans: Select recID, SenderName, SenderAddress, RecName, RecAddress from Sender, Recipient where Sender.Senderid=Recipient.RenderId;
(iii) To display the sender details in ascending order of SenderName.
Ans: Select * from Sender order by SenderName;
(iv) To display number of Recipients from each city.
Ans: Select RecCity,Count(*) from Recipient group by RecCity;
CnorName |
|---|
R singhal |
Amit Kumar |
CneeName |
|---|
Rahul Kishore |
S mittal |
CneeName |
CneeAddress |
|---|---|
P Dhingra |
16/j,Moore Enclave |
B P jain |
13,Block d,a,viha |
(v) SELECT DISTINCT SenderCity FROM
Sender;
Ans:
CBSE Computer Science Solved Revision Tour By Mr. Ravi Kiran ( [email protected] )
