CBSE Guess > Papers > Question Papers > Class X > 2009 > Mathematics > Mathematics
2nd Method : Let O be the centre.
From O draw OD 
BC
AOC = BOC = COA = 
= 
= 1200
BOD = COD =600 ………[From(i)]
Now,inrt . 
ODA,cos60 =
=
2OD=70 OD=35 cm
In rt. ODB,sin 600 = 
=
2BD= 70 
BD=35cm
BC=2BD=2(35)=70
Totalareaof the design= a rod circle–arof ABC
=
(70)2 -
)2
………..
=(70)2 
=4900
= 175(88–36.33)
=175 X 51.67=9042.25 cm2 )
| Mathematics 2009 Question Papers Class X | |||||||||
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CBSE 2009 Question Papers Class X