CBSE Guess > Papers > Question Papers > Class X > 2009 > Mathematics > Mathematics

Sol.

Part I : See Theorem 6, Page (xxxii).

Part II : AP = AR = 7 cm …(Given theorem)
QC = RC = 5 cm …(Given theorem)
BP = AB – AP
= 10 – 7 = 3 cm
BQ = BP = 3 cm …(Given theorem)
 BC = BQ + QC = 3 + 5 = 8 cm

Q. 29. The age of a father is twice the square of the age of his son. Eight years hence, the age of the father will be 4 years more than three times the age of his son. Find their present ages. 6

Sol: Let the present age of Son = x years and the present age of Father = 2x²years According to the problem

Mathematics 2009 Question Papers Class X
Delhi		Outside Delhi		Compartment Delhi		Outside Delhi		Foreign
	Set 1 (PDF)		Set 1 (PDF)		Set 1		Set 1		Set 1 (PDF)
					Set 2		Set 2
					Set 3		Set 3